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2 years ago

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After completing an experiment to determine gravimetrically the percentage of water in a hydrate, a student reported a value of

38 percent. The correct value for the percentage of water in the hydrate is 51 percent. Which of the following is the most likely explanation for this difference.A. Strong initial heating caused some of the hydrate sample to spatter out of the crucibleB. The dehydrated sample absorbed moisture after heatingC. The amount of the hydrate sample used was too smallD. The crucible was not heated to constant mass before useE. Excess heating caused the dehydration sample to decompose

1 answer:

zzz [600]2 years ago

4 0

Answer:

A. Strong initial heating caused some of the hydrate sample to spatter out of the crucible.

Explanation:

Hi

The percentage of water in the sample is lower than expected.

A. Strong initial heating caused some of the hydrate sample to spatter out of the crucible:

If part of the sample is splashed from the crucible the mass of water detected will be less.

B. The dehydrated sample absorbed moisture after heating:

If the sample absorbs water after heating the percentage of water would be higher than expected.

C. The amount of the hydrate sample used was too small:

Depending on the sample size, different procedures can be chosen for analysis.

D. The crucible was not heated to constant mass before use:

In many occasions the crucible is heated next to the sample and not in previous form.

E. Excess heating caused the dehydration sample to decompose:

If the sample decomposes during heating, the analysis should be discarded.

success with your homework

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Answer:

Explanation:

Translated:

Calculate the amount of sugar (C12 H22 O11) in the morning tea if a teaspoon contains 5g of sugar?

Given parameters

Mass of sugar = 5g

Unknown:

Amount of the sugar =?

Solution:

A mole is the amount of substance that contains avogadro's number of particles i.e 6.02 x 10²³

Therefore, to find the number of moles contained in the teaspoon of sugar we use the expression below:

Number of moles = $\frac{mass}{molar mass}$

Molar mass of C₁₂H₂₂O₁₁ = (12x12) + (1x22) + (16x11) = 342g/mol

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maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ = (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

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Mass=9.2g
Volume=12.3

$\boxed{\sf Density=\dfrac{Mass}{Volume}}$

$\\ \sf\longmapsto Density=\dfrac{9.2}{12.3}$

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Answer:

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Explanation:

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$PV=nRT$

where,

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Putting values in above equation, we get:

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<u>1.76 g is the mass of Ne is in the container.</u>

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