0.0821 L-atm/mol-K
8.314 kPa-L/mol-K
Answer:
Explanation:
S is in 3d period, so it has 3 levels
1 level has 2 electrons, 2d level 8 electrons, 3d level 6 electrons
Half life of the reaction is :-101.9 min
a→b
25% reacted means 75% remains
t=42 min
Rate constant
k=(2.303/t)(log a/a-x)
k=(2.303/42)(log 100/100-25 )
k=(0.054) (log 100/75)
k=(0.054)(0.1249)
k=0.0068per min
half life
t1/2=(0.693/k)
=(0.693/0.0068)
=101.9 min
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Answer:
Q = 16163.88 Joules
Explanation:
Given the following data;
Initial temperature, T1 = -25°C
Final temperature, T2 = 150°C
Mass = 45.5 g
Specific heat capacity of ice = 2.03 J/g°C
To find the quantity of heat required;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 150 - (-25)
dt = 150 + 25
dt = 175°C
Substituting into the formula, we have;
Q = 16163.88 Joules