Answer:
A
Explanation:
because it can share and remain with ither electrons
Skeletal structure is missing, so i have attached it.
Answer:
Option B: Omega 6 fatty acid
Explanation:
Arachidonic Acid is defined as an essential and unsaturated fatty acid. It's usually found in animal and human fat including the liver, brain, and also glandular organs. While in animals, it is a constituent of their phosphatides.
Arachidonic Acid is formed as a result of the synthesis from dietary linoleic acid and it's a preliminary stage in the biosynthesis of prostaglandins, thromboxanes, and leukotrienes.
In short, Arachidonic acid is basically a long-chain fatty acid which is a C20, Omega 6 polyunsaturated fatty acid that has four Z-double bonds.
There should be 2 since there’s 2 D atoms in the reaction.
Since the nucleophile is the actual attacking molecule or molecule that starts the reaction and allows for further steps in the mechanism to occur, it is the limiting reagent, as based on the amount of the nucleophile you have, the reaction will tend to proceed until you run out. The excess would be the sodium hydroxide, it is union part of the solution.
Answer:
6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O
Explanation:
First, we need to write the half-reactions:
2Br⁻ → Br₂ + 2e⁻ Oxidation -Balanced yet-
XeO₃ → Xe Reduction
To balance the reduction in acidic aqueous solution we need to add waters in the other side of the reaction as oxygens are present:
XeO₃ → Xe + 3H₂O
And H⁺ as hydrogens from water we have:
XeO₃ + 6H⁺ → Xe + 3H₂O
To balance the charge:
<h3>XeO₃ + 6H⁺ + 6e⁻ → Xe + 3H₂O Reduction -Balanced-</h3><h3 />
To cancel out the electrons of both half-reaction we need to multiply oxidation 3 times:
6Br⁻ → 3Br₂ + 6e⁻
XeO₃ + 6H⁺ + 6e⁻ → Xe + 3H₂O
And the balanced reaction in acidic aqueous solution is the sum of both half-reactions:
<h3>6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O </h3>