Answer:
Explanation:
Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Keq, is 7.8 x 102.
In the living E. coli cells,
[ATP] = 7.9 mM;
[ADP] = 1.04 mM,
[glucose] = 2 mM,
[glucose 6-phosphate] = 1 mM.
Determine if the reaction is at equilibrium. If the reaction is not at equilibrium, determine which side the reaction favors in living E. coli cells.
The reaction is given as
Glucose + ATP → glucose 6-phosphate + ADP
Now reaction quotient for given equation above is
![q=\frac{[\text {glucose 6-phosphate}][ADP]}{[Glucose][ATP]}](https://tex.z-dn.net/?f=q%3D%5Cfrac%7B%5B%5Ctext%20%7Bglucose%206-phosphate%7D%5D%5BADP%5D%7D%7B%5BGlucose%5D%5BATP%5D%7D)
so,
⇒ following this criteria the reaction will go towards the right direction ( that is forward reaction is favorable until q = Keq
Answer:
Likely to gain electrons
Explanation:
The atom shown is likely to gain additional electrons to complete its electronic configuration.
- Since this is a neutral specie, the number of protons and electrons are the same.
- The atom has 16 electrons
- the number of valence electrons is 6
- If the atom gains two additional electrons, the octet configuration is attained
- Also, the atom can lose 6 electrons to become an octet
The atom will prefer to gain additional 2 electrons to give an octet configuration.
Carboxylic acids and alcohols have higher boiling point
than other hydrocarbons due to their polarity and from the fact that they form
very strong intermolecular hydrogen bonding. This is due to the large
difference in their electronegativity that forms between the oxygen and the
hydrogen atom.
