Answer:
1mpm(1 meters per minute) Explanation: Speed:Distance/time 25/25=1 plz mark as brainliest
<u>Answer:</u> The moles of chlorine gas produced is 5.5 moles
<u>Explanation:</u>
We are given:
Moles of HCl = 11 moles
For the given chemical reaction:
By Stoichiometry of the reaction:
4 moles of HCl produces 2 moles of chlorine gas
So, 11 moles of HCl will be produced from of chlorine gas
Hence, the moles of chlorine gas produced is 5.5 moles
Answer:
Benzaldehyde is less electrophilic than acetaldehyde
Explanation:
Electrophilicity of carbonyl carbon depends on it's positive charge density.
In benzaldehyde, phenyl group can act as an electron donating group towards carbonyl group due to it's electron donating resonating effect.
In acetaldehyde, methyl group can act as an electron donating group towards carbonyl group due to it's electron donating inductive effect.
We know that resonating effect are more stronger than inductive effect.
Henece, it is expected that positive charge density on carbonyl carbon is much lower in benzaldehyde than acetaldehyde.
So, benzaldehyde is less electrophilic than acetaldehyde.
Resonating effect of phenyl group has been shown below.
Lead chromate is a precipitate that is formed on the reaction of lead nitrate with sodium chromate. The best method to separate this precipitate from the solution is filtration.
- A precipitate can be defined as an insoluble solid formed in a chemical reaction. It appears as a cloudy and resulted after a reaction.
- The lead chromate is yellow colored precipitate that forms after the reaction of lead nitrate with sodium chromate.
- The process of separation of insoluble solids from the liquids by the use of filters is known as filtration. Insoluble solids are also called as precipitates these precipitates are formed in a chemical reaction.
- Filtration will help in separation of insoluble solid yellow colored lead chromate precipitate from the solution using a porous material or filter that selectively inhibits the passage of solid precipitate material and allows the solution to pass through it.
Learn more about filtration:
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