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2 years ago

Convert 1.50μm2 to square meters

1 answer:

4 0

1 micro meter = $10^{-6} meters$
1 μm ^2 = 1 μm*1μm = $10^{-6} *10^{-6} = 10^{-12}$ meters

1.5 μm^2 = 1.5 * $10^{-12}$ meters

μm^2 is a unit for surface. First you want to convert μm to meters which is unit for length and if you multiply units for length you get unit for surface.

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Two. O and E are both vowels

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What are some natural resources that are limited on earth

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Answer:

oil, ores, and fossils.

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2 years ago

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c

gtnhenbr [62]

Answer:

1.13 × 10⁶ g

Explanation:

Let's consider the reduction of aluminum (III) from Al₂O₃ to pure aluminum.

Al³⁺ + 3 e⁻ → Al

We can establish the following relations:

1 Ampere = 1 Coulomb / second
The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
1 mole of Al is produced when 3 moles of electrons circulate
The molar mass of Al is 26.98 g/mol.

The mass of aluminum produced under these conditions is:

$90.0 s \times \frac{1s}{620c} \times \frac{96,468c}{1mole^{-} } \times \frac{3mole^{-}}{1molAl} \times \frac{26.98gAl}{1molAl} =1.13 \times 10^{6} g Al$

6 0

2 years ago

Dimethyl sulfoxide [(ch3)2so], also called dmso, is an important solvent that penetrates the skin, enabling it to be used as a t

Bas_tet [7]

The molecular formula of dimethyl sulfoxide is $(CH_{3})_{2}SO$ . Molar mass of dimethyl sulfoxide is 78.13 g/mol. Calculate number of moles as follows:

$n=\frac{m}{M}=\frac{7.14\times 10^{3} g}{78.13 g/mol}=91.38 mol$

From the molecular formula, 1 mole of dimethyl sulfoxide contains 2 moles of Carbon, 6 moles of Hydrogen, 1 mole of Sulfur and 1 mole of oxygen.

Thus, 91.38 moles of dimethyl sulfoxide will have:

Carbon :

$n_{C}=2\times 91.38 moles=182.77 moles$

Hydrogen:

$n_{H}=6\times 91.38 moles=548.28 moles$

Sulfur:

$n_{S}=1\times 91.38 moles=91.38 moles$

Oxygen:

$n_{O}=1\times 91.38 moles=91.38 moles$

Since, 1 mole of an element equals to $6.023\times 10^{23}$ atoms thus, number of atoms can be calculated as:

Carbon:

$1 mole\rightarrow 6.023\times 10^{23} atoms$

Thus,

$182.77 moles\rightarrow 182.77\times 6.023\times 10^{23} atoms=1.10\times 10^{26} atoms$

Hydrogen:

$1 mole\rightarrow 6.023\times 10^{23} atoms$

Thus,

$548.28 moles\rightarrow 548.28\times 6.023\times 10^{23} atoms=3.30\times 10^{26} atoms$

Sulfur:

$1 mole\rightarrow 6.023\times 10^{23} atoms$

Thus,

$91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms$

Oxygen:

$1 mole\rightarrow 6.023\times 10^{23} atoms$

Thus,

$91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms$

Therefore, number of C, S, H and O atoms are $1.10\times 10^{26}, 5.50\times 10^{25}, 3.30\times 10^{26} and 5.50\times 10^{25} atoms$ respectively.

4 0

3 years ago

2Cu+S→Cu2S

xenn [34]

15.9 grams is the amount of copper sulfate this reaction will produce.

Given:

The reaction between copper and sulfur:

$2Cu +S\rightarrow Cu_2S$

12.7 grams of copper completely reacts with 3.2 grams of sulfur to give copper sulfide.

To find:

The mass of copper sulfide produced

Solution

Mass of copper used by the scientist = 12.7 g

Mass of sulfur used by the scientist = 3.2 g

Mass of copper sulfide this reaction will produce. =?

According to the law of conservation of mass:

Total mass of reactants = Total mass of products

The total mass of reactants in the reaction = R = 12.7 g + 3.2 g = 15.9 g

The total mass of product formed in the reaction = P

P = R = 15.9 g

Mass of copper sulfide this reaction will produce = 15.9 g

15.9 grams is the amount of copper sulfate this reaction will produce.

Learn more about the law of conservation of mass:

brainly.com/question/14236219?referrer=searchResults

brainly.com/question/101125?referrer=searchResults

3 0

2 years ago