2Cu+S→Cu2S
1 answer:
15.9 grams is the amount of copper sulfate this reaction will produce.
Given:
- The reaction between copper and sulfur:
- 12.7 grams of copper completely reacts with 3.2 grams of sulfur to give copper sulfide.
To find:
The mass of copper sulfide produced
Solution
Mass of copper used by the scientist = 12.7 g
Mass of sulfur used by the scientist = 3.2 g
Mass of copper sulfide this reaction will produce. =?
According to the law of conservation of mass:
Total mass of reactants = Total mass of products
The total mass of reactants in the reaction = R = 12.7 g + 3.2 g = 15.9 g
The total mass of product formed in the reaction = P
P = R = 15.9 g
Mass of copper sulfide this reaction will produce = 15.9 g
15.9 grams is the amount of copper sulfate this reaction will produce.
Learn more about the law of conservation of mass:
You might be interested in
Answer:- 0.800 moles of the gas were collected.
Solution:- Volume, temperature and pressure is given for the gas and asks to calculate the moles of the gas.
It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:
PV=nRT
Since it asks to calculate the moles that is n, so let's rearrange this for n:
V = 19.4 L
T = 17 + 273 = 290 K
P = 746 mmHg
we need to convert the pressure from mmHg to atm and for this we divide by 760 since, 1 atm = 760 mmHg
P = 0.982 atm
R =
Let's plug in the values in the equation to get the moles.
n = 0.800 moles
So, 0.800 moles of the gas were collected.