We know that
the equation of a circle is
(x-h)²+(y-k)²=r²
r=3 units
where the center is the point (h,k)
if the circle is tangent to the y-axis at (0,2) and <span> its center in Quadrant I
</span><span>then
the center is the point (0+3,2)--------> (3,2)
therefore
the answer is
</span>(x-3)²+(y-2)²=9
see the attached figure
the equation of a circle is
(x-h)²+(y-k)²=r²
r=3 units
where the center is the point (h,k)
if the circle is tangent to the y-axis at (0,2) and <span> its center in Quadrant I
</span><span>then
the center is the point (0+3,2)--------> (3,2)
therefore
the answer is
</span>(x-3)²+(y-2)²=9
see the attached figure