Answer:
-1
Step-by-step explanation:
Hello :) ok so to find AC you would have to use sin. It would be sin70= x/4. To find AC you would have to multiply 4 by sin70 which is 3.758 or to the nearest hundredth would be 3.76. I hope I helped, if you need a more in depth explanation lmk
Step-by-step explanation:
3x + 10 < 3
3x + 7 < 0
3x < -7
x < -7/3 = -2.3333...
or
2x - 5 >= 5
2x >= 10
x >= 5
x < -7/3 or x >= 5
2 gallons were left at the end of the day
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
