Answer:
The fraction of the area of ACIG represented by the shaped region is 7/18
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
In the square ABED find the length side of the square
we know that
AB=BE=ED=AD
The area of s square is
where b is the length side of the square
we have
substitute
therefore
step 2
Find the area of ACIG
The area of rectangle ACIG is equal to
substitute the given values
step 3
Find the area of shaded rectangle DEHG
The area of rectangle DEHG is equal to
we have
substitute
step 4
Find the area of shaded rectangle BCFE
The area of rectangle BCFE is equal to
we have
substitute
step 5
sum the shaded areas
step 6
Divide the area of of the shaded region by the area of ACIG
Simplify
Divide by 5 both numerator and denominator
therefore
The fraction of the area of ACIG represented by the shaped region is 7/18
Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet,
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :
Putting all the values,
.....(1)
For maximum height, put
Put t = 1.875 in equation (1)
So, the maximum height reached by the ball is 61.25 m.
In order to find the average you have to add up all the data values and then find the sum of the data values.
So on average he ran about 82.5 miles.
The square root of 45 is simplified to 3 root 5. Rounded in decimal form, 6.708
The volume of soup in the cylindrical can is 100.48 inches cube.
<h3>How to find the volume of a cylindrical can?</h3>
We have to find the volume of the soup in a cylindrical can of height 8 inches and 4 inches across the lid.
The volume of the soup is the volume of the cylindrical can.
Therefore,
volume of the cylindrical can = πr²h
where
- r = radius of the cylinder
- h = height of the cylinder
Therefore,
h = 8 inches
r = 4 / 2 = 2 inches
volume of the soup in the cylindrical can = πr²h
volume of the soup in the cylindrical can = π × 2² × 8
volume of the soup in the cylindrical can = π × 4 × 8
volume of the soup in the cylindrical can = 32π
Therefore,
volume of the soup in the cylindrical can = 32 × 3.14
volume of the soup in the cylindrical can = 100.48 inches³
learn more on volume here:brainly.com/question/23207959
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