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2 years ago

Please explain how to solve this thank you

Mathematics

1 answer:

kotegsom [21]2 years ago

5 0

What is the question

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T: 3(t + 3) + 5(3 + 2t) – 76 = 0

Setler [38]

Answer:

$\huge\boxed{\sf t = 4}$

Step-by-step explanation:

$\sf 3(t+3)+5(3+2t)-76 = 0\\\\Expanding \ Parenthesis\\\\3t + 9 + 15 + 10t -76 = 0\\\\13t + 24 -76 = 0\\\\13t - 52 = 0\\\\Add \ 52 \ to \ both \ sides\\\\13t = 52\\\\Dividing\ both\ sides\ by\ 13\\\\t = 52/13\\\\t = 4\\\\\rule[225]{225}{2}$

Hope this helped!

6 0

2 years ago

Read 2 more answers

Help me please ......

oksano4ka [1.4K]

-4 = x - 7
-4 + 7 = x
3 = x

Therefore x = 3

4 0

2 years ago

Determine the value of X. Please help. 50 POINTS

iris [78.8K]

Answer:

102.86

Step-by-step explanation:

cos 55 = 59/x

x = 59/cos 55

x = 102.86

5 0

2 years ago

–4x – 7 = y x2 – 2x – 6 = y Which statement is true? There are no real number solutions. There is one unique real number solutio

Aleksandr [31]

Answer:

<h3>There is one unique real number solution at (–1, –3)</h3>

Step-by-step explanation:

Given the two linear equation

–4x – 7 = y ...1

x² – 2x – 6 = y ...2

Equating the left hand side of both equations since they are equal to the same variable y will give;

$-4x-7=x^{2} -2x-6\\collecting\ the\ like\ terms\\x^{2} -2x+4x-6+7 = 0\\x^{2} +2x+1 = 0\\x^{2} +x+x+1 = 0\\x(x+1)+1(x+1)=0\\(x+1)^{2}=0\\ taking\ square\ root\ of\ both\ sides\\x+1 = 0\\x = -1\\$

Substituting x=1 into equation 1 we have;

$y=-4(-1)-7\\y=4-7\\y = -3$

This means there is only one unique real number solution at (-1, -3)

7 0

2 years ago

Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 71.2 inches

Alexxandr [17]

Answer:

0.7857

Step-by-step explanation:

Given :

Mean = 69 inches

Standard deviation, = 2.8 inches

The Zscore of a man who is 71.2 inches

The ZSCORE is obtained using the relation :

Zscore = (Score, x - mean) / standard deviation

Zscore = (71.2 - 69) / 2.8

Zscore = 2.2 / 2.8

Zscore = 0.7857

3 0

2 years ago