Answer:
29.4 meters
Step-by-step explanation:
Given the following :
A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
distance it moved between two positions. Use the "distance on the number line "formula
Initial Position or distance of submarine before ascension = 56.8 meters
Final position after ascension = 27.4 meters
The distance moved by the submarine between the two positions can be obtained by.
(Initial distance - Final distance)
(56.8 - 27.4) = 29.4 meters
The correct answer will be -4x - 10 which is A. X subtracts to the other side and makes it -4x, then 6 +-4 = -10
AB∥CD and m∠4=85°.
so
<1 = 180° - 85°
<1 = 95°
Because AB∥CD so <5 = <1 = 95° (corresponding angles are equal)
Answer
<5 = 95°
Answer:
Step-by-step explanation:
Given
Required
Find the height
The volume is calculated as thus:
This gives
Apply difference of two squares
Subtract 15 from both sides
Using a calculator to factorize, we have:
Split
or
or
x has complex roots for
Hence:
Recall that: