19) A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
1 answer:
Answer:
29.4 meters
Step-by-step explanation:
Given the following :
A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
distance it moved between two positions. Use the "distance on the number line "formula
Initial Position or distance of submarine before ascension = 56.8 meters
Final position after ascension = 27.4 meters
The distance moved by the submarine between the two positions can be obtained by.
(Initial distance - Final distance)
(56.8 - 27.4) = 29.4 meters
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