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2 years ago

This is the question that i need help with. pls help me

Mathematics

1 answer:

Law Incorporation [45]2 years ago

6 0

Answer:

x = 5, y = 6

Step-by-step explanation:

For the triangles to be congruent then corresponding sides are equal

that is BC = ED and AC = AD, that is

x = y - 1 → (1)

3x - 2 = 2y + 1 → (2)

substitute x = y - 1 into (2)

3(y - 1) - 2 = 2y + 1

3y - 3 - 2 = 2y + 1

3y - 5 = 2y + 1 ( subtract 2y from both sides )

y - 5 = 1 ( add 5 to both sides )

y = 6

substitute y = 6 into (1) for corresponding value of x

x = 6 - 1 = 5

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Please help me with this

skelet666 [1.2K]

D) 8.17 x 10^8

910000000 - 93000000 = 817000000

817000000 ---> 8.17 x 10^8

5 0

2 years ago

Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams

hram777 [196]

Answer:

$X(16)=25.71grams$

Step-by-step explanation:

let $X(t)$ denote grams of $C$ formed in $t$ mins.

For $X grams$ of $C$ we have:

$\frac{2}{3}Xg$ of A and $\frac{1}{3}Xg$ of B

Amounts of A,B remaining at any given time is expressed as:

$40-\frac{2}{3}Xg$ of A and $50-\frac{1}{3}Xg$ of B

Rate at which C is formed satisfies:

$\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}$

Apply the initial condition, $X(0)=0$ ,to the expression above

$0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}$

Now at $X(8)=15$ :

$15=90-\frac{90}{90\times 8k+1} \ ->75=\frac{90}{720k+1}\\k=0.0002778$

Substitute in X(t) to get

$X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71$

5 0

2 years ago

I SERIOUSLY NEED HELP HERE!!!!!

Semenov [28]

The correlation coefficient is A. 0.438.

8 0

2 years ago

U= {1,2,3,4,5,6,7,8,}, A={1,4,5,7}, B= {2,5,6,7,}, and C= {3,4,6,7}

choli [55]

Answer:

a. {1, 2, 3, 4, 5, 6, 7}

b. {1, 2, 3, 4, 5, 6, 8}

c. {4, 5, 7}

d. {1, 4, 5}

Step-by-step explanation:

The union of two sets is the list of elements in either set. The intersection of two sets is the list of elements in both sets. The complement of a set is the list of elements in the universal set that are not in the set being complemented. The complement of a set can be indicated with an apostrophe: A' is the complement of set A, for example.

B∪C = {2, 5, 6, 7} ∪ {3, 4, 6, 7} = {2, 3, 4, 5, 6, 7}

A∪(B∪C) = {1, 4, 5, 7} ∪ {2, 3, 4, 5, 6, 7} = {1, 2, 3, 4, 5, 6, 7}

B∩C = {2, 5, 6, 7} ∩ {3, 4, 6, 7} = {6, 7}

A ∩ (B∩C) = {1, 4, 5, 7} ∩ {6, 7} = {7}

(A∩(B∩C))' = {7}' = {1, 2, 3, 4, 5, 6, 8}

A∩Β = {1, 4, 5, 7} ∩ {2, 5, 6, 7} = {5, 7}

Α∩C = {1, 4, 5, 7} ∩ {3, 4, 6, 7} = {4, 7}

(A∩B)∪(A∩C) = {5, 7} ∪ {4, 7} = {4, 5, 7}

(A∩B')∪(A∩C') = A∩(B'∪C') = A∩(B∩C)'

(B∩C)' = {6, 7}' = {1, 2, 3, 4, 5, 8}

A∩(B∩C)' = {1, 4, 5, 7} ∩ {1, 2, 3, 4, 5, 8} = {1, 4, 5}

<em>Additional comment</em>

In part (d) we made use of De Morgan's law for sets:

B'∪C' = (B∩C)'

We also made use of the distributive property for sets:

A∩(B∪C) = (A∩B)∪(A∩C)

6 0

1 year ago

The equation 4[x + 2(3x −7 )] = 22x − 65 was simplified to write the equivalent equation of 28x-56=22x-65. What is the solution

bekas [8.4K]

28x - 56 = 22x - 65
28x - 22x = -65 + 56
6x = - 9
x = -9/6
x = - 3/2 or - 1 1/2 <===

4 0

2 years ago

Read 2 more answers