w represents width
4w represents length
d represents diagonal
w2 + (4w)2 = d2
w2 + 16w2 = d2
17w2 = d2
±w√17 = d
The diagonal is the width times √17.
Answer:
N(1)=50 is a minimum
N(15)=4391.7 is a maximum
Step-by-step explanation:
<u>Extrema values of functions
</u>
If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.
We are given a function (corrected)
(a)
First, we take its derivative
Solve N'(t)=0
Simplifying
Solving for t
Only t=1 belongs to the valid interval 
Taking the second derivative
Which is always positive, so t=1 is a minimum
(b)
N(1)=50 is a minimum
(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15
(d)
N(15)=4391.7 is a maximum
Answer: the first option is the correct answer.
Step-by-step explanation:
Triangle ABC is a right angle triangle.
From the given right angle triangle,
AB represents the hypotenuse of the right angle triangle.
With m∠A as the reference angle,
AC represents the adjacent side of the right angle triangle.
BC represents the opposite side of the right angle triangle.
To determine the tangent of angle A, we would apply the Tangent trigonometric ratio. It is expressed as
Tan θ, = opposite side/adjacent side. Therefore,
Tan A = 5/5√3 = 1/√3
Rationalizing the surd, it becomes
1/√3 × √3/√3
Tan A = √3/3
Answer:
< 1 = 88
< 2 = 92
Step-by-step explanation:
First add 4x - 4 + 4x = 180
X = 23
4(23) - 4 = 88
4(23) = 92
Answer:
x^2 + 8x + 16
Step-by-step explanation:
(x + 4) (x+ 4) multiply x by x and x by 4.
x^2 + 4x
Then multiply 4 by x and 4 by 4.
4x + 16
Then combine like terms.
x^2 + 4x + 4x +16
x^2 + 8x + 16
