A bus can travel 63 miles in 1.4 hours. If its speed is increased

Suppose you take

kati45 [8]

Answer:

a current will be induced.

Explanation:

4 0

2 years ago

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Jessica does not like how her BestFriend has been treating her around others. When confronted, the friend says Jessica is being

Eva8 [605]

She is sad and feels left out because they are treating her badly. Hope this helps :)

7 0

2 years ago

A vertical straight wire 35.0 cmcm in length carries a current. You do not know either the magnitude of the current or whether t

12345 [234]

Answer:

$1.714\ \text{A}$

Explanation:

F = Magnetic force = 0.018 N

B = Magnetic field = 0.03 T

L = Length of wire = 35 cm

$\theta$ = Angle between current and magnetic field = $90^{\circ}$

Magnetic force is given by

$F=IBL\sin\theta\\\Rightarrow I=\dfrac{F}{BL\sin\theta}\\\Rightarrow I=\dfrac{0.018}{0.03\times 35\times 10^{-2}\times \sin90^{\circ}}\\\Rightarrow I=1.714\ \text{A}$

The magnitude of the current is $1.714\ \text{A}$ .

8 0

2 years ago

A 5.00 g bullet traveling 355 m/s is stopped by lodging in the side of a building. The heat produced is shared between the build

steposvetlana [31]

Answer:

Explanation:

Given

mass of bullet $m=5\ gm$

speed of bullet $v=355\ m/s$

bullet is stopped by building and heat produced is shared between building and bullet

Kinetic Energy of bullet is converted into Thermal energy

Kinetic Energy of bullet $K=\frac{1}{2}mv^2$

$K=0.5\times 5\times 10^{-3}\times (355)^2$

$K=315.06\ J$

So 315.06 J of Energy is converted in to thermal energy

7 0

2 years ago

13. Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distanc

Gennadij [26K]

This question is incomplete, the complete question is;

Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distance and the direction. We will investigate in detail just two directions. With charges available in the simulation (all the charges are either positive or negative 1 nC increments).

how do you create a dipole with dipole moment 1 x 10-9 Cm with a direction for the dipole moment pointing to the right. Make a table below that shows the amounts of charge and the distance between the charges. There are many correct answers

Answer:

Given the data in question;

Dipole moment P = 1 × 10⁻⁹ C.m

now dipole pointing to the right;

P→

$_{-\theta }$ (-) ---------------->(+) $_{+\theta }$

d

so let distance between the dipoles be d

∴ P = d $\Theta$

Let $\Theta_{1}$ = 1 nC

so

P = d $\Theta$

1 × 10⁻⁹ = 1 × 10⁻⁹ × d

d = (1 × 10⁻⁹) / (1 × 10⁻⁹)

d = 1 m

Also Let $\Theta_{2}$ = 2 nC

so

P = d $\Theta$

1 × 10⁻⁹ = 2 × 10⁻⁹ × d

d = (1 × 10⁻⁹) / (2 × 10⁻⁹)

d = 0.5 m

Also Let $\Theta_{3}$ = 3 nC

so

P = d $\Theta$

1 × 10⁻⁹ = 3 × 10⁻⁹ × d

d = (1 × 10⁻⁹) / (3 × 10⁻⁹)

d = 0.33 m

such that;

charge distance

1 nC 1.00 m

2 nC 0.50 m

3 nc 0.33 m

4 nC 0.25 m

5 nC 0.20 m

5 0

2 years ago