let dogs be heads. Let cats be tails. A coin has two sides, in which you are flipping two of them. Note that there can be the possible outcomes
h-h, h-t, t-h, t-t.
How this affects the possibility of two dogs & two cats. Note that there are 1/2 a chance of getting those two (with the others being one of each), which means that out of 4 chances, 2 are allowed.
2/4 = 1/2
50% is your answer
Heads represents cats and tails represents dogs. There is two coins because we are checking the probability of two pets. You have to do the experiment to get your set of data, once you get your set of data, you will be able to divide it into the probability for cats or dogs. To change the simulation to generate data for 3 pets, simply add a new coin and category for the new pet.
Hope this helps you out!
You must follow the steps below:
1. First, you should apply the dstributive property:
=(x²-<span>8x+15/3x)(8x/x-3)
=(8</span>x³-64x²+120x)/3x(x-3)
2. As you can see, the common factor in the numerator is: "8x". So, you have:
=8x(x²-8x+15)/3x(x-3)
3. Then, when you simplify, you obtain:
=8(x²-8x+15)/3(x-3)
Therefore, the solution is: 8(x²-8x+15)/3(x-3)
Answer: The answer is 8
Step-by-step explanation:
It’s Kinda obvious if your teachers asks u to explain its 12 1/2 - 4 1/2 which equals 8 1
2
+
4 1
2
=
17
Calculation steps:
12 1
2
+
4 1
2
= (12 + 4) + (
1
2
+
1
2
)
= 16 +
1 + 1
2
= 16 +
2
2
= 16 +
2 ÷ 2
2 ÷ 2
= 16 +
1
1
= 8 hope this helps
