Answer:
30 students they are including the students that are also planning to participate in other sports to.
=600(1+0.1/2)^8
Use the calculator to get the answer :-)
Answer:
$0.75
Step-by-step explanation:
Consider any one of the values given in the table.
Cost of 5 tickets = $3.75
So, cost of 1 ticket
= $3.75/5
= $0.75
Verification:
Verify the answer by other values.
Cost of 10 tickets = $7.50
So, cost of 1 ticket
= $7.50/10
= $0.75
Cost of 15 tickets = $11.25
So, cost of 1 ticket
= $11.25/15
= $0.75
Cost of 20 tickets = $15.00
So, cost of 1 ticket
= $15.00/20
= $0.75
The cost of 1 ticket is same in all cases.
Hence, verified.
Answer: f(120°) = (√3) + 1/2
Step-by-step explanation:
i will solve it with notable relations, because using a calculator is cutting steps.
f(120°) = 2*sin(120°) + cos(120°)
=2*sin(90° + 30°) + cos(90° + 30°)
here we can use the relations
cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)
sin(a + b) = cos(a)*sin(b) + cos(b)*sin(a)
then we have
f(120°) = 2*( cos(90°)*sin(30°) + cos(30°)*sin(90°)) + cos(90°)*cos(30°) - sin(90°)*sin(30°)
and
cos(90°) = 0
sin(90°) = 1
cos(30°) = (√3)/2
sin(30°) = 1/2
We replace those values in the equation and get:
f(120°) = 2*( 0 + (√3)/2) + 0 + 1/2 = (√3) + 1/2
<span> x/2 - 3 = 7
Add 3 to both sides
x/2=10
Multiply 2 on both sides
Final Answer: B. 20</span>