Answer:
I'd say the correct answer is A
Explanation:
hope this helps:)
sorry if its wrong:(
Answer:
0.600 g/cm³
Explanation:
Step 1: Given data
- Height of the cylinder (h): 6.62 cm
- Diameter of the cylinder (d): 2.34 cm
- Mass of the cylinder (m): 17.1 g
Step 2: Calculate the volume of the cylinder
First, we have to determine the radius, which is half of the diameter.
r = d/2 = 2.34 cm/2 = 1.17 cm
Then, we use the formula for the volume of the cylinder.
V= π × r² × h
V= π × (1.17 cm)² × 6.62 cm
V = 28.5 cm³
Step 3: Calculate the density (ρ) of the sample
The density is equal to the mass divided by the volume.
ρ = m/V
ρ = 17.1 g/28.5 cm³
ρ = 0.600 g/cm³
Answer:
A neutral Beryllium atom has two (2) valence electrons
Explanation:
<em>Beryllium, Be,</em> is a group 2 element on the periodic table. Its atomic number is 4.
Generally, atomic number equals number of electrons, which means a neutral Beryllium atom contains four (4) electrons: two (2) in the inner shells and 2 in the outer shell (valence electrons), which can take part in a chemical reaction and participate in chemical bonding.
Answer:
Kindly check the explanation section.
Explanation:
From the description given in the question above, that is '' H subscript f to the power of degree of the reaction" we have that the description matches what is known as the heat of formation of the reaction, ∆fH° where the 'f' is a subscript.
In order to determine the heat of formation of any of the species in the reaction, the heat of formation of the other species must be known and the value for the heat of reaction, ∆H(rxn) must also be known. Thus, heat of formation can be calculated by using the formula below;
∆H(rxn) = ∆fH°( products) - ∆fH°(reactants).
That is the heat of formation of products minus the heat of formation of the reaction g specie(s).
Say heat of formation for the species is known as N(g) = 472.435kj/mol, O(g) = 0kj/mol and NO = unknown, ∆H°(rxn) = −382.185 kj/mol.
−382.185 = x - 472.435kj/mol = 90.25 kJ/mol
A. proton donating is often referring to Hydrogen donating in acids. See the extra H+ in common acids: HCl, H2SO4
