Cobalt-60 is a radioactive isotope used to treat cancers. A gamma ray emitted by this isotope has an energy of 1.33 MeV (million
electron volts; 1 eV = 1.602 x 10¹⁹ J). What is the frequency (in Hz) and the wavelength (in m) of this gamma ray?
1 answer:
Answer:
E = 1.33 MeV = 2.13 x 
J
v = wavelength = E / h = 2.13 x / 6.626 x 
= 3.2 x 
m
f = frequency = c / 3.2 x m = 3 x 
/ 3.2 x = 9.375 x Hz
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[H+] = 1.74 x 10⁻⁵
Explanation:
By definition pH = -log [H+]
Therefore, given the pH, all we have to do is solve algebraically for [H+] :
[H+] = antilog ( -pH ) = 10^-4.76 = 1.74 x 10⁻⁵
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Answer:
hello I am interested in the position and would like to know if you have any questions please feel free to contact me at any time if
Moles of H⁺ released by each mole of acid = 3
Moles of H⁺ released = 3
Moles of OH⁻ released = 1.75
Moles of H⁺ remaining = 3 - 1.75 = 1.25 mol/dm³
pH = -log[H⁺]
pH = -log(1.25)
pH = -0.1
Hope this helps, have a nice day ahead!
