Answer:
1) Fe = 69.9%
O = 31.1%
2) H = 5.19%
O = 16.5%
N = 28.9%
C = 49.5%
Explanation:
One easy way to do percent compositions is to assume you have 100g of a substance.
1) Lets say we have 100g of Fe2O3.
The total molar mass would be:
The molar mass of the Fe2 alone is:
Thus, the grams of Fe2(out of a 100) could be calculated by multiplying 100g * the molar mass ratio of Fe2 to the whole:
Which is approximately 69.9%.
We can find the amount of O3 by simply subtracting, as the rest of the compound is made of O3. Thus, the % composition of O3 is 31.1%
You can then do this same process to the next question, getting us the following:
H = 5.19%
O = 16.5%
N = 28.9%
C = 49.5%
Cations are formed by losing electrons in the valence shell of atoms. There are more protons than electron ions making the atom more positive.
According to your equation, for every mole of iron oxide (Fe2O3), it takes 3 moles of carbon monoxide (CO). So for 1.75 moles, it takes 3 times as many moles of CO.
1.75 x 3 = 5.25 moles of CO.
I think your product is CO2. Dalton's Law sayeth that the coefficients tell us the ratios of moles. So if you hve 1.75 moles of Fe(III)oxide, 3*1.75 moles of CO are needed (in theory) to react completely. The answer is requested in moles, so you need go no further.
A loss<span> of </span>kinetic energy<span> in the atoms or molecules of a </span>sample of matter<span> will result in the cooling of the sample.</span>
