Multiply both 1/6=11/66, 3/11=9/66. 1/6 is bigger.
Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
Answer:
the 2 one
Step-by-step explanation:
The answer for this problem would be 7x+6
Let's solve this problem step-by-step.
4x−3+3x+9
=4x+−3+3x+9
Step 1: Combine Like Terms.
=4x+−3+3x+9
=(4x+3x)+(−3+9)
So, the answer for this problem would be 7x+6.
