The distance between two points is given by:
d² = (x₂-x₁)² + (y₂ - y₁)²
9 = (x₂ - 4)² + (y₂ - 2)²
Now, we can check different ordered pairs in this equation to see which satisfies it:
The one that satisfies this equation is (4 , -1).
Answer:
4.
Step-by-step explanation:
(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α
But sec^2 α = 1 + tan^2 α so
sec^2 α - tan^2α = 1 + tan^2 α - tan^2α
= 1
so 1 = (sec α - tan α)(sec α + tan α) = 1/4 * x where x is sec α + tan α
1/4 * x = 1
x = 4.
x+6 is x+6. It's an expression. Not sure what you need help with.
First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2