Answer:
Explanation:
We must use the Nernst equation
1. Write the equation for the cell reaction
If you want the reduction potential, the pH 5.65 solution is the cathode, and the cell reaction is
<u> E°/V</u>
Anode: H₂(1 bar) ⇌ 2H⁺(1 mol·L⁻¹) + 2e⁻; 0
Cathode: <u>2H⁺(pH 5.65) + 2e⁻ ⇌ H₂(1 bar)</u>; <u> 0 </u>
Overall: 2H⁺ (pH 5.65) ⇌ 2H⁺(1 mol·L⁻¹); 0
Step 2. Calculate E°
(a) Data
E° = 0
R = 8.314 J·K⁻¹mol⁻¹
T = 25 °C
n = 2
F = 96 485 C/mol
pH = 5.65
Calculations:
T = 25 + 273.15 = 298.15 K
Answer:
Explanation: was given the equation: Ca(OH)2 + H3PO4 --> H2O + Ca3(PO)4, which I balanced to:
3 Ca(OH)2 + 2 H3PO4 --> 6 H2O + Ca3(PO)4
I am supposed to find
a) How many grams of calcium phosphate are produced from the reaction of 25.0g of Ca(OH)2 with excess H3PO4.
b) If 0.139 moles of Ca(OH)2 react with 0.58 moles H3PO4, determine the grams of H2O produced and the grams of the excess reagent left after the reaction.
Answer: Interphase
Explanation: This is the stage in mitosis where the cell grows, and DNA is being replicated. This happens during the Synthesis Phase of Interphase.
Answer:
13 years
Explanation:
From;
0.693/t1/2 = 2.303/t log (No/N)
Where;
t1/12 = half-life of Cobalt-60 = 5.3 years
t = time taken = the unknown
No = mass of radioactive material originally present = 5.2 g
N = mass of radioactive material at time t = 0.95 g
Substituting values;
0.693/5.3 = 2.303/t log (5.2/0.95)
0.131 = 2.303/t(0.738)
0.131 = 1.6996/t
t = 1.6996/0.131
t = 12.97 years
t = 13 years(to the nearest whole number)
Although it is omitted, the reaction equation for the decomposition of phosphorus pentachloride is:
PCl₅ → PCl₃ + Cl₂
The equilibrium constant's equation then becomes:
Kc = [PCl₃]*[Cl₂] / [PCl₅]
Kc = (0.02 * 0.02) / 0.0095
Kc = 0.042
The equilibrium constant is 0.042.