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2 years ago

Which describes an object in projectile motion? Check all that apply.

2 answers:

8 0

When an object is thrown near the Earth's surface than it has a projectile motion. The thrown object is called projectile. The projectile is influenced by the gravity and moves along a curved path.<span>A projectile has an initial velocity, which is either horizontal or upward at an angle.</span>
An object in projectile motion is described with the following statements:
- <span>Gravity acts to pull the object down.
</span>- The path of the object is curved.

VladimirAG [237]2 years ago

5 0

IT - Gravity acts to pull the object down.

- The path of the object is curved.

that the answer i got it Right on the test

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What is the volume of an object with a density of 2.6 g/cm³ and a mass of 30.5g?

inessss [21]

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density}$

From the question

mass of object = 30.5 g

Density = 2.6 g/cm³

The volume is

$volume = \frac{30.5}{2.6} \\ = 11.7307692...$

We have the final answer as

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2 years ago

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234+34.1 add and round to 2 significant figures

marin [14]

Like this? 234+34.1= 268.1 then round. If it is less than 5 then you round down if it is more then you round up. Because it is less the final number would be 268.1=268

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2 years ago

Why has the acidity of the ocean increased over the years?

aalyn [17]

Answer:

I think it's A

Explanation:

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2 years ago

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the

Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

$\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}$

$P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}$

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

#SPJ4

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1 year ago