The Area is the width times the height: A = w x h;
Then, 64 = w x h;
h = 4 + w;
64 = 4w + w^2;
w^2 + 4w - 64 = 0;
We solve this equation: w1 ≈ 6,24 > 0 (okay); w2 ≈ - 10,24 < 0 (not okay);
Finally, h1 ≈ 10,24;

4 0

2 years ago

What is the value of x in the equation 3x -1/9 y = 18, when y = 27? 5 7 45 63

almond37 [142]

Answer:

$x=7$

Step-by-step explanation:

we have

$3x-\frac{1}{9}y=18$

Substitute the value of y=27 in the equation and find the value of x

$3x-\frac{1}{9}(27)=18$

$3x-3=18$

$3x=18+3$

$3x=21$

$x=7$

4 0

2 years ago

Please help me with the problem

mixas84 [53]

Let's see what we're working on here

$\frac{1}{2} - 2(m) =?$
? = 0
$Simplify this →$ $\frac{1}{2}$

$\frac{1}2y} - 2(m) = ?$

$\frac{2(m)(2)}{2}$

$\frac{1 - 4(m)}{2} = ?$

$\frac{1 - 4(m)}{2} = 2$

$-4(m) + 1 = 0$
Subtract ( - )the number 1 from each of your sides on this part

4(m) = 1
Multiply( ×) the number -1 to your sides for this part of the equation

Therefore, the value of m is $\frac{1}{4}$
$m = \frac{1}{4}$

3 0

3 years ago

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