Point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)
slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7
a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)
2nd one
Answer:
x=14√3 and y=28
Step-by-step explanation:
This is a 30, 60, 90 triangle. We have to multiply 14 by 2 to get the hypotenuse. In this case, the hypotenuse is y. 14x2 is equal to 28. Therefore, y=18. The long side is equal to the small side times the √3. Therefore, x is equal to 14√3. Therefore, x=14√3 and y=28.
If this has helped you please mark as brainliest
The answer is b he went up 7 when he had to go down 7
Answer:
Step-by-step explanation:
Use Pythagorean theorem,
base²+altitude² = hypotenuse²
x² + 14² = 40²
x² + 196 = 1600
x² = 1600 - 196
x² = 1404
x = √1404
x = 37.47 ft
Answer:
The measure of the angle JKG is:
m∠JKG = 56°
Step-by-step explanation:
<u>Given</u>
m∠JKG = 76-2x
m∠FHK = 6x-4
J is a midpoint of the segment FG and K is a midpoint of the segment GH.
<u>To determine</u>
m∠JKG = ?
Given that J is a midpoint of the segment FG and K is a midpoint of the segment GH. Thus, making two similar triangles, ΔJGK and ΔFGH
We know that two triangles are similar if the only difference is size. So, the angles remain the same.
so m∠JKG and m∠FHK are equal.
i.e.
m∠JKG = m∠FHK
substitute m∠JKG = 76-2x and m∠FHK = 6x-4
76-2x = 6x-4
6x+2x = 76 + 4
8x = 80
divide both sides by 8
8x/8 = 80/8
x = 10
Therefore, the value of x = 10
As
m∠JKG = 76-2x
substitute x = 10
m∠JKG = 76 - 2(10)
= 76 - 20
= 56°
Therefore, measure of the angle JKG is:
m∠JKG = 56°