Answer:
Following are the responses to the given question:
Step-by-step explanation:
When x is squared, it's going to be bigger by the conclusion because the larger the faster. 
consistently exceeds 
, regardless of the price of X.
5x+3 is always 3 more so than 5x.
In particular, this can be classified according to its pathways 
So can alternatively just say "eventually," which means because when x really is big, you need to find one another's values. Then just select x=100, then plug it into every single other. To confirm this order:
So, the ascending order must be the right order!
Answer:it’s b
Step-by-step explanation:
On edn
8.7/2=q/4
multiply both sides by 4: q=8.7/2*4
multiply both sides by 2: 2q=8.7 times 4
refine the equation: 2q=34.8
multiply both sides by 10: 20q=348
Divide both sides by 20: 20q/20=348/20
refine the equation for the final answer: q=87/5
Step 2: She did not simplify under the square root correctly
under the square root:
(-6)^2 =36
and -4(5)(-8) =160
therefore under the square root it needs to be square root of 36+160 which is square root of 196.
That answer is 14 when square rooted
Answer:
The pairs are (13,15) and (-15,-13).
Step-by-step explanation:
If n is an odd integer, the very next odd integer will be n+2.
n+1 is even (so we aren't using this number)
The sum of the squares of (n) and (n+2) is 394.
This means
(n)^2+(n+2)^2=394
n^2+(n+2)(n+2)=394
n^2+n^2+4n+4=394 since (a+b)(a+b)=a^2+2ab+b^2
Combine like terms:
2n^2+4n+4=394
Subtract 394 on both sides:
2n^2+4n-390=0
Divide both sides by 2:
n^2+2n-195=0
Now we need to find two numbers that multiply to be -195 and add up to be 2.
15 and -13 since 15(-13)=-195 and 15+(-13)=2
So the factored form is
(n+15)(n-13)=0
This means we have n+15=0 and n-13=0 to solve.
n+15=0
Subtract 15 on both sides:
n=-15
n-13=0
Add 13 on both sides:
n=13
So if n=13 , then n+2=15.
If n=-15, then n+2=-13.
Let's check both results
(n,n+2)=(13,15)
13^2+15^2=169+225=394. So (13,15) looks good!
(n,n+2)=(-15,-13)
(-15)^2+(-13)^2=225+169=394. So (-15,-13) looks good!
