Answer:
Yes, the shapes are similar. Note, the angles are equivalent and the sides are scales of each other satisfying the requirements for similarly.
Step-by-step explanation:
For a shape to be similar there are two conditions that must be met. (1) Must have equivalent angles (2) Sides must be related by a scalar.
In the two triangles presented, the first condition is met since each triangle has three angles, 90-53-37.
To test if the sides are scalar, each side must be related to a corresponding side of the other triangle with the same scalar.
9/6 = 3/2
12/8 = 3/2
15/10 = 3/2
Alternatively:
6/9 = 2/3
8/12 = 2/3
10/15 = 2/3
Since the relationship of the sides is the scalar 3/2 (Alternatively 2/3), then we can say the triangles meet the second condition.
Given that both conditions are satisfied, then we can say these triangles are similar.
Note, this is a "special case" right triangle commonly referred to as a 3-4-5 right triangle.
Cheers.
I wanna say B but i don’t remember i had that question before though
If there is a triangle with Sid a and b then sina b/✓a2+b2and seven=✓a2+b2/a
Answer:
b=2.5
p=6
Step-by-step explanation:
Take the fraction and simplify it. So 10/8 would be 5/4
You multiply the 2 by 2, giving you h/4
So now you have 5/4=h/4
h=5 but now you have to divide both by 2 again so it can go back to the original fraction.
5÷2=2.5 and 4÷2=2
Second Problem! 4/2 is equal to 2/1
You can also multiply 4 by 3 to get the numerator as 12. Multiply the 4 by 3 and the 2 by 3
Now you have 12/6= 12/p
So p is 6
