Answer :
Part A : The partial pressure of argon is, 0.795 atm
Part B : The partial pressure of ethane is, 0.505 atm
Explanation :
<u>Part A :</u>
First we have to calculate the moles of argon.
Molar mass of argon = 39.95 g/mole
Now we have to calculate the partial pressure of argon.
Using ideal gas equation :
PV = nRT
where,
P = Pressure of argon = ?
V = Volume of argon = 1.00 L
n = number of moles of argon = 0.0325 mole
R = Gas constant =
T = Temperature of argon =
Putting values in above equation, we get:
The partial pressure of argon is, 0.795 atm
<u>Part B :</u>
Now we have to calculate the partial pressure of ethane.
As we know that,
Total pressure = Partial pressure of argon + Partial pressure of ethane
1.300 atm = 0.795 atm + Partial pressure of ethane
Partial pressure of ethane = 1.300 - 0.795
Partial pressure of ethane = 0.505 atm
The partial pressure of ethane is, 0.505 atm