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2 years ago

What are the square roots of 81?

Mathematics

2 answers:

HACTEHA [7]2 years ago

8 0

It would be 9 Hope this helps.

k0ka [10]2 years ago

4 0

The square root of 81 is 9.

Explanation:
9 times 9 is 81
9 to the power of 2 is 81

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What is 6x(-496)=19x12

vichka [17]

Answer:

-19/248

Step-by-step explanation:

4 0

2 years ago

Carol walked 1 1/3 miles on Monday. 35/6 miles on Tuesday, and 2 miles on Wednesday. About how far did she walk altogether?

Dmitry_Shevchenko [17]

Answer:

9 1/6 miles

Step-by-step explanation:

Add the mixed number by the improper fraction.

1 + 1/3 + 35/6

Solve the fractions first.

In order to have both of the fractions have the same denominator, find the Least Common Multiple of both of the fractions.

1/3 = 2/6

2/6 + 35/6 = 37/6

Turn the improper fraction into a mixed number by dividing the the numerator by the denominator. When you get your quotient, use the remainder as the new numerator over the denominator.

37/6 = 6 1/6

Now, add the 1.

6 1/6 + 1 = 7 1/6

Now, add the 2 miles that Carol walked on Wednesday.

7 1/6 + 2 = 9 1/6

So, Carol walked about 9 1/6 miles on Monday, Tuesday, and Wednesday all together.

4 0

2 years ago

Read 2 more answers

Let f(x) = 3x+5 and g(x) = x^2. Find g(x)/f(x) and state its domain

lianna [129]

Answer:

1/x-2; domain is the set of all real numbers except 2

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

2 years ago

Calculate the force created from an object with a mass of 1250 grams and an acceleration of 3 m/s^2

abruzzese [7]

The force created by the object is 3.75 Newton.

Given

Mass of the object (m) = 1250 grams

Convert 1250 grams to kilograms by dividing it by 1000.

Mass (m) = 1.25 kg

Acceleration of the body (a) = 3 $m/s^{2}$

From Newton's second law we know $F= m *a$

By Substituting in the above equation we get

Force = 1.25 x 3

Force = 3.75 $kg/m /s^{2}$

It can also be written as force = 3.75 N

Hence Force created by the body is 3.75 Newton.

To know more about Force refer

brainly.com/question/13191643?referrer=searchResults

8 0

5 months ago