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2 years ago

Let f(x) = 3x+5 and g(x) = x^2. Find g(x)/f(x) and state its domain

Mathematics

2 answers:

lianna [129]2 years ago

7 0

Answer:

1/x-2; domain is the set of all real numbers except 2

Step-by-step explanation:

rodikova [14]2 years ago

3 0

Answer:

All real x except x = -5/3.

Step-by-step explanation:

g(x) / f(x)

= x^2/ (3x + 5)

We can't have a zero denominator so the domain is

All real x except x = -5/3.

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Find the missing side lengths. Leave your answers as radicals in simplest form.

Leto [7]

9514 1404 393

Answer:

x = 18
y = 9

Step-by-step explanation:

The ratios of side lengths in a 30°-60°-90° triangle are ...

1 : √3 : 2

In the same order, the given side lengths are ...

y : 9√3 : x

Comparing these two sets of ratios, we see that we can make the first equal to the second by multiplying by 9:

9(1) : 9√3 : 9(2) = y : 9√3 : x

Then y = 9·1 = 9, and x = 9·2 = 18.

The missing side lengths are x = 18, y = 9.

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2 years ago

What is point slope form for (4,5) and (2,-6)

nordsb [41]

Answer: 11/2

Its simple math ig

8 0

2 years ago

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Pick the decimal equivalent to 3 9/100

Sidana [21]

If you have pick it, then you should be offered choices and you should include them in the question.

The answer is 3.09

4 0

2 years ago

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Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩

klemol [59]

$\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle$

$\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt$

$\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle$

$\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1$

$\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2$

$\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3$

With the initial condition $\mathbf r(0)=\langle4,6,3\rangle$ , we find

$\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9$

$\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6$

$\dfrac92\cdot0^2+C_3=3\implies C_3=3$

So the particular solution to the IVP is

$\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle$

4 0

2 years ago

The length of a rectangle is 4 more than the width. The entire perimeter is 38".

Novosadov [1.4K]

L = 4 + w
perimeter = 38

38 = w + 4 + w
2w = 34
w = 17

L = 4 + 17
L = 21

i am a mathematics teacher. if anything to ask please pm me

4 0

2 years ago