12.25 g of aluminium nitrate Al(NO₃)₃ are needed to prepare the solution.
Explanation:
First we determine the number of moles of aluminium nitrate:
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume (L)
number of moles of aluminium nitrate = 0.230 × 0.250
number of moles of aluminium nitrate = 0.0575 moles
Then we calculate the mass of aluminium nitrate Al(NO₃)₃:
mass = number of moles × molecular weight
mass of aluminium nitrate = 0.0575 × 213
mass of aluminium nitrate = 12.25 g
Learn more about:
number of moles
brainly.com/question/13314627
molar concentration
brainly.com/question/6341703
#learnwithBrainly