A spaceship accelerates from 0m/s to 40m/s in 5 seconds. What is the acceleration of the spaceship
1 answer:
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You can use Newton's Second Law which states:
Plug in given information:
This is closest to option b which is your answer.
Plug in given information:
This is closest to option b which is your answer.
The magnitude of the acceleration of the ball while coming to rest is 477.43 m/s²
The direction of the acceleration of the ball is downwards
The given parameters
initial velocity of the ball, u = 0
height above the ground, h = 2.2 m
time of motion of the ball, t = 96 ms = 0.096 s
The magnitude of the acceleration of the ball while coming to rest is calculated as;
let the downwards direction of the acceleration be positive
The direction of the acceleration of the ball is downwards
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