Answer:
We need 67.2 grams of 02. There will be produced 92.421 grams of CO2
Explanation:
<u>Step 1:</u> The balanced equation
C6H12O6 (aq) + 6O2 (g) = 6CO2 (g) + 6H2O (l)
<u>Step 2</u>: Data given
We can see that for 1 mole C6H12O6 consumed, we need 6 moles of O2 to produce 6 moles of CO2 and 6 moles of H2O
The mass of glucose is 63.0g
The molar mass of glucose is 180.156 g/mole
The molar mass of O2 is 32 g/mole
The molar mass of CO2 is 44.01 g/mole
<u>Step 3: </u>Calculate number of moles of glucose
Number of moles of glucose = mass of glucose / molar mass of glucose
Number of moles of glucose = 63 grams /180.156 g/moles = 0.35 moles
<u>Step 4:</u> Calculate number of moles of oxygen ( and CO2)
For 1 mole of glucose we need 6 moles of O2 to produce 6 moles of CO2 and 6 moles of H2O
So for 0.35 moles of glucose we need 6*0.35 = 2.1 moles of O2 to produce 2.1 moles of CO2 and 2.1 moles of H2O
<u>Step 5:</u> Calculate mass of oxygen ( and CO2)
mass of oxygen = number of moles of oxygen * Molar mass of oxygen
mass of oxygen = 2.1 moles * 32 g/mole = 67.2 g O2 (≈ 67 grams)
mass of CO2 = number of moles of CO2 * Molar mass of CO2
mass of CO2 = 2.1 moles * 44.01 g/mole = 92.421 grams
We need 67.2 grams of 02. There will be produced 92.421 grams of CO2