Answer:
18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Explanation:
Mercury oxide has molar mass of 216.6 g/ mol. It gas a molecular formula of HgO.
The decomposition of mercury oxide is given by the chemical equation below:
2HgO ----> 2Hg + O₂
2 moles of HgO decomposes to produce 1 mole of Hg
2 moles of HgO has a mass of 433.2 g
433.2 g of HgO produces 216.6 g of Hg
18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg
Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Answer:
The biological significance is that it is the normal human body temperature and also the optimum temperature of the enzyme.
Explanation:
- Enzymes are biological catalysts that speed up the rate of chemical reactions.
- Enzymes catalyze specific reactions by working on a specific substrate to convert it into a product.
- The rate of enzyme activity depends on several factors which include pH, temperature, substrate concentration, and enzyme concentration among others.
- Enzymes work best at a specific pH and temperature known as optimum pH and optimum temperature respectively.
- In this case, enzyme amylase works best at a temperature of 37° C which is equivalent to the normal human body temperature.
Cu(NO3)2>NO2+CuO+O2 balanced: 2Cu(NO3)2=4NO2+2CuO+O2
Answer:
K = 2.96x10⁻¹⁰
Explanation:
Based on the initial reaction:
N2O4 ⇄ 2NO2; K = 1.5x10³
Using Hess's law, we can multiply this reaction changing K:
3 times this reaction:
3N2O4 ⇄ 6NO2; K = (1.5x10³)³ =3.375x10⁹
The inverse reaction has a K of:
6NO2 ⇄ 3N2O4 K = 1/3.375x10⁹;
<h3>K = 2.96x10⁻¹⁰</h3>
That is false (please mark me brainliest)
