11.27 mol of carbon dioxide gas is equal to 252.45 L or 270.48 L
<h3>Further explanation</h3>
Given
11.27 mol of CO2
Required
Volume of gas
Solution
If the conditions are assumed to be at the STP state (Standard Temperature and Pressure) at T 0 ° C and P 1 atm, then Vm is 22.4 liters/mol.
so for 11.27 moles the total volume is:
11.27 mol x 22.4 L = 252.45 L
But if the conditions are assumed to be at RTP (Room Temperature and Pressure), Conditions at T 25 ° C and P 1 atm. Vm = 24 liters/mol, then the volume of CO2:
11.27 mol x 24 L = 270.48 L.
Answer:
The answer is explained below:
Explanation:
Given the chemical equation:
N2H4(g)+H2(g)→2NH3(g)
The standard enthalpy of formation is given by the following formula:
ΔH^0 rxn = ∑ B reactants - ∑ product
-187.78 kJ/mol = [( 1x B N-N) + (1 x B N-H ) + (1 x b H-H)] - [ 6 x B N-H]
-187.78 kJ/mol = [( 1x B N-N) +(4 x 391 kJ/mol) + (1 x 436 kJ/mol)] - [ 6x 391 kJ/mol ]
-187.78 kJ/mol = B N-N + (1564 + 436 - 2346) kJ/mol
B = 158.22 kJ/mol
So, in this case the enthalpy of N-N bond is 158 kJ/mol
229.25 mL of isopropyl alcohol
425.75 mL of water
Explanation:
Knowing that the solution have a 35.0 % (v/v) isopropyl alcohol in water, we can calculate the volume of each component as following.
volume of isopropyl alcohol = (35/100) × solution volume
volume of isopropyl alcohol = 0.35 × 655 mL = 229.25 mL
Now, knowing the volume of isopropyl alcohol we can determine the volume of water.
volume of the solution = volume of isopropyl alcohol + volume of water
volume of water = volume of the solution - volume of isopropyl alcohol
volume of water = 655 mL - 229.25 mL = 425.75 mL
Learn more about:
percent by volume concentration
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Answer:
The answer is C.
Explanation:
Mass is converted to the energy binding a nucleus together.
1. Figure out a problem
2. Research
3. Hypothesis
4. Experiment
5. Analyze results
6. Conclusion
7. Communicate your results
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