Answer:
Adding H₂O(g) to the system.
Explanation:
- Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
<u><em>1) Removing H₂O(g) from the system:</em></u>
- This will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the removal of H₂O(g) from the system.
<u><em>2) Adding CH₃CHO(g) to the system :</em></u>
- This will increase the concentration of the products side, so the reaction will be shifted to the left side to suppress the adding CH₃CHO(g) to the system.
<u><em>3) Removing C₂H₂(g) from the system:</em></u>
- This will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the removal of C₂H₂(g) from the system.
<u><em>4) Adding H₂O(g) to the system:</em></u>
- This will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the addition of H₂O(g) to the system.
- <u><em>So, it is the right choice.</em></u>
Answer:
you did not give the specific heat like formula like it takes 1kj to raise 28grams of water by 10 grams
Weight is properly defined as how much gravity acts upon an object.
I hope this helps!
<u>Answer:</u>
<em>We know water can exist in all three states be it solid or liquid or gas the only difference between the three states is the temperature at which they exist. </em>
<u>Explanation:</u>
When the temperature moves towards colder region the state of water changes to solid while when the temperature moves to water region the state of water changes to gas.
This little experiment can be done with the help of ice at room temperature. The more ice is applied to water it will turn to ice but removal of eyes in room temperature. And will make it turn to water and complete removal of eyes with application of heat would make it into vapour.
Answer:
810 pm
Explanation:
Step 1: Given and required data
- Velocity of the atom (v): 490 m/s
- Mass of a hydrogen atom (m): 1.67 × 10⁻²⁷ kg
- Planck's constant (h): 6.63 × 10⁻³⁴ J.s
Step 2: Calculate the de Broglie wavelength of the hydrogen atom
We will use de Broglie's equation.
λ = h / m × v
λ = 6.63 × 10⁻³⁴ J.s / 1.67 × 10⁻²⁷ kg × 490 m/s = 8.10 × 10⁻¹⁰ m
Step 3: Convert 8.10 × 10⁻¹⁰ m to picometers
We will use the conversion factor 1 m = 10¹² pm.
8.10 × 10⁻¹⁰ m × 10¹² pm/1 m = 810 pm
