Total internal energy change is equals to -44.83kJ
Q=-73.2kJ (negative sign indicates that heat was released by the system),
P= 50.0atm
ΔU= Q + W, FIRST LAW OF THERMODYNAMICS..........(1)
ΔV= Final volume - initial volume= 2.00 litre - 7.60litre= -5.60litre
work done by the system (w)= -PΔV
w= -(50.0×(-5.60)) atm×litre= 280atm litre
1 atm litre= 101.325J
w= 280 ×101.325 J= 28,371J
1kJ=1000J,
w=28.37KJ,
so putting in the values in equation (1)...
energy change(ΔU) = -73.2 kJ + 28.37 kJ
= - 44.83 kJ
Answer:
It would be 3 times as much gravity or 7 times
Explanation:
Zn (s) -> Zn+2 (aq) + 2e-
Zn (s) with a neutral charge is oxidized and looses two electrons in the process to form ZnCl2 (aq) where Zn has a charge of 2+.
Answer:
The correct answer is option E.
Explanation:
Structures for the reactants and products are given in an aimage ;
Number of double bonds in oxygen gas molecule = 1
Number of double bonds in nitro dioxide gas molecule = 1
Number of single bond in in nitro dioxide gas molecule = 1
Number of triple bonds in nitrogen gas molecule = 1
(pure element)
(pure element )
The enthalpy of the given reaction is 15.86 kcal.