First we need to find a common denominator
=
now we can add them
+
=
In Step 2, Lara did not ensure that the second diamter was perpendicualr to the first diameter she drew.
The correct steps should be:
Step 1: Use the straightedge to draw a diameter of the circle. Label the points at which the diameter touches the circle as A and B.
Step 2: Draw a second diameter <em>perpendicular to the first diameter</em>. Label the points at which the second diameter touches the circle as C and D.
Step 3: Join the end points of the two diameters to form a square.
Q represents the number of invitations without a response. Q is equal to 253
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
