1j=1newton*meter
force=mass*accel
200N=55x
200/55=3.636......
3.636...-2=1.636.....
1.636 is the deceleration resulting from friction hence the force of friction is 1.636*55=90newtons
90newtons*distance of 10 meters= 900 j of work done by friction
Answer:
The speed of the light through that liquid is 
.
Explanation:
Given that,
The refractive index of the liquid, 
We need to find the speed of light through that liquid. Let the speed of light in liquid is v. The relation between the refractive index and the speed of light in the medium. So,
So, the speed of the light through that liquid is . Hence, this is the required solution.
Answer:
1.0x10^-4
Explanation:
First, in order to do this, we need to calculate the volume of 1 simple atom of Ar. Using the formula of the volume of a sphere we have the following
Converting A to cm:
0.97 * 1x10^-8 = 9.7x10^-9 cm
Now the volume:
V = 4/3π(9.7x10^-9)³
V = 3.82x10^-24 cm³
We know that 1 cm³ is 1 mL, and 1 L is 1000 mL so:
V = 3.82x10^-24 mL / 1000 = 3.82x10^-27 L
Now, using avogadro's number, we should get the total volume of all atoms of Ar so:
3.82x10^-27 * 6.02x10^23 = 2.3x10^-3 L
Finally, at STP the volume of an ideal gas is 22.4 L so:
2.3x10^-3 / 22.4 = 1.03x10^-4
With two significant figure, it would be 1.0x10^-4
The physics problem to find the unknown has applied physics principles will be the following:
The simplified expression for coefficient of kinetic friction is 0.097.
The given parameters:
g = 9.8 m/s²
a = 3.6 m/s²
θ=27.0∘
The simplified expression for coefficient of kinetic friction is calculated as follows;
μkmgcosθ = mgsinθ − ma
m(μkgcosθ) = m(gsinθ − a)
μkgcosθ = gsinθ − a
The practise of using physics as a science to assist people and address their issues is known as applied physics.
Engineering is distinct from it since engineers deal with clearly defined problems. Applying physics to the development of new technologies or the resolution of engineering issues is the work of applied physicists.
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