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2 years ago

Which type of circuit is a continuous loop that allows the flow of current along its intended path?

Physics

2 answers:

Lemur [1.5K]2 years ago

7 0

C

Closed circuits allow current to flow

zhannawk [14.2K]2 years ago

5 0

A C) closed circuit is a continuous loop that allows the flow of current along its intended path.

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phase, color, and ductility are all examples of what type of property? chemical changeable physical external

svet-max [94.6K]

<span>Phase, color, and ductility are all examples of physical external properties</span>

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2 years ago

How many atoms are in 3.5 moles of sulfur

irina [24]

There are 2.1077x10^24 atoms of sulfur in 3.50 mols of sulfur.

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2 years ago

A hockey puck with a mass of 0.16 kg travels at a velocity of 40 m/s toward a goalkeeper. The goalkeeper has a mass of 120 kg an

Ainat [17]

Answer:

Explanation:

Momentum is the product of mass of a body and its velocity.

Given the mass of the puck m1 = 0.16kg

velocity of the puck v1 = 40m/s

Given the mass of the goalkeeper m2 = 120kg

velocity of the goalkeeper v2= 0m/s (goal keeper at rest)

The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is expressed as:

m1v1 + m2v2 (their momentum will be added since they collide)

= 0.16(40) + 120(0)

= 0.16(40) + 0

= 6.4kgm/s

Let us calculate their common velocity using the conservation of momentum formula;

m1u1 + m2u2 = (m1+m2)v

6.4 = (0.16+120)v

6.4 = 120.16v

v = 6.4/120.16

v = 0.053m/s

Hence after collision, both objects move at a velocity of 0.053m/s

Momentum of the puck after collision = m1v

Momentum of the puck after collision = 0.16*0.053m/s

Momentum of the puck after collision = 0.0085kgm/s

Momentum of the keeper after collision = m2v

Momentum of the keeper after collision = 120*0.053m/s

Momentum of the keeper after collision = 6.36kgm/s

From the calculation above, it can be seen that the keeper has the greater momentum after the puck was caught since the momentum of the keeper after collision is greater than that of the puck

4 0

2 years ago

3) An electron moves in a circular orbit of radius 0.11 mm, counterclockwise as you look down at it, moving in a plane above and

andrey2020 [161]

Answer:

B = 0.15 T

Explanation:

To find the magnitude of the magnetic field you use the following formula:

$B=\frac{mv}{qr}$ ( 1 )

m: mass of the electron = 9.1*10^-31 kg

v: velocity of the electron = 3*10^6 m/s

q: charge = 1.6*10^-19

r: radius = 0.11mm = 0.11*10^-3 m

You replace the values of the parameters in the equation (1).

$B=\frac{(9.1*10^{-31}kg)(3*10^6\frac{m}{s})}{(1.6*10^{-19}C)(0.11*10^{-3}m)}=0.15T$

the magnetic field has a magnitude of 0.15 T

4 0

2 years ago

In each of the given pairs, choose which element will have the bigger atom. Give reasons for your choice. (a) Mg (atomic number

Dafna1 [17]

Answer:

Mg (atomic number 12)

K (atomic number 19)

Explanation:

The size of an atom is estimated in terms of its atomic radius.

The atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance (d) between two nuclei in the solid - state of metals.

Across a period, atomic radii decrease progressively from left to right.
This is due to the progressive increase in the nuclear charge without increase in the number of electronic shells.
Down a group, atomic radii increase progressively due to the successive shells of electrons being added which have been compensated for by the increase in nuclear charge.

Cl is further right of Mg in the third period

K is below Na in the first group

3 0

2 years ago