K.E =1/2mv2
M=6kg
V=3m/s
K.E=1/2 X 6 X 3 X 3
=1/2 X 6 X 9
=27 J
3000 N of friction exists between the bear and the tree.
The bear goes down at a constant speed, thus there is no acceleration. The forces add up to zero. As a result, upward friction and downward weight result in zero
i.e.,
F-mg=0
F = mg
F = (300 kg)/10 (gravitational acceleration)
3000 N frictional force equals F.
How does friction force work?
- Friction is the force that prevents two solid objects from rolling or sliding over one another. Even though frictional forces, such as the traction required to walk without slipping, may be advantageous, they can also be a significant hindrance to motion.
Between solid surfaces, there are three basic types of friction:
- Rolling
- Sliding.
- Static. They are graded from strongest to weakest. Fluid friction happens when liquids or gasses are mixed together.
To learn more about Friction force, visit:
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Answer:
a) The magnitude of the current is 24.19 A
b) The angle is 90°
Explanation:
a) Given:
B = magnetic field = 44 µT = 44x10⁻⁶T
r = distance = 11 cm = 0.11 m
The current is:
b) Because the current flows from the west to the east, therefore, the angle is 90 degrees from the north.
Answer:
1/r
Explanation:
The magnetic field produced by a current in a wire decreases with distance from the wire, this means the magnetic field produced by a currents is inversely proportional to it's distance from the wire.
Let E be magnetic field and r distance of wire
We have that,
E is inversely proportional to r
(E)×(1/r)
Answer:
The tension in string P is 25 N, while that of Q is 85 N.
Explanation:
Considering the conditions for equilibrium,
i. Total upward force = Total downward force
+ = 110 N
ii. Taking moment about P,
clockwise moment = anticlockwise moment
110 × (2.5 - 0.8) = × (3 - 0.8)
110 × 1.7 = × 2.2
187 = 2.2
=
= 85 N
From the first condition,
+ = 110 N
+ 85 N = 110 N
= 110 - 85
25 N
Therefore, the tension in string P is 25 N while that of Q is 85 N.