Assuming the distribution is continuous, you have
If instead the distribution is discrete, the value will depend on how the interval of number between 1 and 29 are chosen - are they integers? evenly spaced rationals? etc
Answer:
A = 76.85
B =65.28
Step-by-step explanation:
(30/100)A = 10 + (20/100)B
0.3A - 0.2B = 10 ...... equation (i)
(30/100)B + 35 = (20/100)A
0.2A - 0.3B = 35 ........ equation (ii)
From equation (i)
0.3A = 10 - 0.2B
A = (10 - 0.2b) / 0.3
A = 33.33 - 0.67B ........equation (iii)
Put equation (iii) into equation (ii)
0.2(33.33 - 0.67B) - 0.3B = 35
6.67 - 0.134B - 0.3B = 35
0.434B = 35 - 6.67
B = 28.33 / 0.434
B = 65. 275 = 65.28
Put B = 65.28 into equation (i)
0.3A - 0.2B = 10
0.3A - 0.2(65.28) = 10
0.3A - 13.056 = 10
0.3A = 10 + 13.056
A = 23.056/ 0.3
A = 76.85
Actually Welcome to the concept of expo functions.
f(x) = -8(2)^x - 12 ,
for f(0) ,here substitute x = 0
so we get as ,
==> f(0) = -8(2)^0 -12
==> f(0) = -8-12
==> f(0) = -20
hence, f(0) = -20
<span>-3.66666666667 is da answer
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