Answer:
That is the system.
y = x - 4
y = 4x - 10
If you are looking for the solution then use the method of substitution or the method of elimination.
To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.
161/7=23
<span>162/7=23.1428571429
</span>145/7=<span>20.7142857143
128/7=</span><span>18.2857142857
Obviously, Julie cannot give a fraction of an amount of candy to someone. So that rules out that she had 162, 145, or 128 pieces of candy.
The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.</span>
You have this....
√x > 8
This means that the square root of something is greater than 8.
So plug in everything for x and find the answer.
Anything 64 and below is NOT THE ANSWER.
√64 = 8, and 8 is not greater than 8, so anything 64 and below is wrong.
So the answer is...
D and F.
Answer:
The values of x for which the model is 0 ≤ x ≤ 3
Step-by-step explanation:
The given function for the volume of the shipping box is given as follows;
V = 2·x³ - 19·x² + 39·x
The function will make sense when V ≥ 0, which is given as follows
When V = 0, x = 0
Which gives;
0 = 2·x³ - 19·x² + 39·x
0 = 2·x² - 19·x + 39
0 = x² - 9.5·x + 19.5
From an hint obtained by plotting the function, we have;
0 = (x - 3)·(x - 6.5)
We check for the local maximum as follows;
dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0
6·x² - 38·x + 39 = 0
x² - 19/3·x + 6.5 = 0
x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2
∴ x = 1.288, or 5.045
At x = 1.288, we have;
V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99
V ≈ 22.99 in.³
When x = 5.045, we have;
V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023
Therefore;
V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5
The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.
What problem I don't see anything
