Given:
u(initial velocity)=0
v(final velocity)= 10 m/s
t= 4 sec
Now we know that
v= u + at
Where v is the final velocity
u is the initial velocity
a is the acceleration measured in m/s^2
t is the time measured in sec
10=0+ax4
a=10/4
a=2.5 m/s^2
OK.
But first we need to know . . .
-- Where is Riverdale ?
-- What is the air temperature there right now ?
-- What kind of system is being used now ?
-- Where can we get a complete description of the groundwater system ?
Answer:
d) False. If the angular momentum is zero, it implies in electro without turning, which would create a collapse towards the nucleus, so in both models the moment must be different from zero
Explanation:
Affirmations
a) true. The orbits are accurate in the Bohr model and probabilistic in quantum mechanics
b) True. If both give the same results and use the same quantum number (n)
c) True. If in angular momentum it is quantized, in the Bohr model too but it does not justify it
d) False. If the angular momentum is zero, it implies in electro without turning, which would create a collapse towards the nucleus, so in both models the moment must be different from zero
Answer:
109.385m
Explanation:
In 1 day, the hour hand travels 2 circles, or 4π rad in angular. The distance it travels is its angle times the radius
7.4 * 4π = 93 mm
In 1 day, the minute hand travels 24*60 = 1440 circles, or 1440 * 2π = 2880π rad in angular. The distance it travels is
12.1 * 2880π = 109478 mm
So the distance traveled by the tip of the minute hand that exceed the distance traveled by the tip of the hour hand is
109478 - 93 = 109385 mm or 109.385 m
