Answer: 0.8 nC
Explanation: In order to explain this problem we have top use the expression for the capacitor of parallel plates, which is given by:
C=εo*A/d where A and d are the area and the separation of the plates.
Then we have
V=Q/C so ΔV= Q* Δd/(εo*A)
Q= 100* 0.054*8.85*10^-12/( 0.06)=0.8 nC
<span>Without friction, there will be undamped simple harmonic motion. The force of the spring is proportional to the distance from the equilibrium point. The period of oscillation will be independent of the amplitude.
I hope my answer has come to your help. God bless and have a nice day ahead!</span>
A is the answe for the final temperatures
Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.
Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)
