Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so
x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4
the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=
for x²-4x+16=0
x=
x=
x=
x=
x=
x=
the roots are
x=-4 and 2+2i√3 and 2-2i√3
Answer:
y = 100°
Step-by-step explanation:
I can't see the full question, but I'm guessing you need to find the measure of angle y.
The total angle sum of a polygon can be calculated with the formula
T = 180°(n - 2) where T is the total angle measure, and n i the number of sides.
For our shape, there are 4 sides, so n = 4. Plug that in and simplify...
T = 180°(4 - 2)
T = 180°(2)
T = 360°
We are given 3 of the angles, so angle y is
y = 360 - 107 - 104 - 49
y = 100°
28 x 2 = 56 half dollar coins
The anserws is 88 so your welcome