Julie is corrected since 3×9=27 and you could still divide 27÷3 and have no remainders.
3,11,19,27
11-3=8
3+8= 11
11+8= 19
19+8=27
Add each number by 8
27+8= 35
35+8= 43
Answer is 3,11,19,27,35,43
Answer:
6
Step-by-step explanation:
sorry if im wrong T-T
Answer:
3 Numbers: 15, 21, 35
Step-by-step explanation:
We want number that divide 109 with a remainder of 4.
Thus, it can divide of 109 - 4 = 105
Factors of 105 = 3, 5, 7
Thus for getting two digit number it must be Multiple of any two factors of 105.
i.e. 15, 21 and 35
Hence there are only 3 numbers that divide 109 with a remainder of 4.