Answer:
Percent relative error = 0.191%
Explanation:
Relative error is a measure of accuracy (How closeness is the measure to the accepted value) for a determined data. The formula is:
Percent relative error = |Experimental - Accepted| / Accepted * 100
<em>Where experimental is the average of the data:</em>
(40.220g/mol + 40.654g/mol + 40.314g/mol + 40.165g/mol + 40.554g/mol) / 5 =
40.381g/mol
Replacing using accepted value = 40.304g/mol:
|40.381g/mol - 40.304g/mol| / 40.304g/mol * 100
<h3>Percent relative error = 0.191%</h3>
Answer:
The answer to your question is 1.25 M
Explanation:
Data
Molarity 1 = ?
Volume 1 = 60 ml
Molarity 2 = 0.5 M
Volume 2 = 150 ml
Process
1.- Write the dilution formula
Molarity 1 x Volume 1 = Molarity 2 x Volume 2
-Solve for Molarity 1
Molarity 1 = Molarity 2 x Volume 2 / Volume 1
-Substitution
Molarity 1 = (0.5)(150) / 60
-Simplification
Molarity = 75 / 60
-Result
Molarity = 1.25 M
2LiI+1Br₂-->2LiBr+1I₂
1CsNO₃+1KCl-->1CsCl+1KNO₃
Answer:
Solution A is 1,000 times more acidic than Sol. B
Explanation:
for pH values we use scientific notation:
-log10 c (where c is the hydrogen ion concentration) is used to notate pH value (think of it as a unit)
ie:
10^-2 is sol A 10^-5 is sol B
5-2 is 3
10^-3 = 1000
there's a diff of 1,000 between the solutions.
